NECO GENERAL MATHEMATICS ANSWERS ARE AVAILABLE FOR FREE

Maths obj complete and verified
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1-10 deacdacbbe
11-20 cbaeebdacc
21-30 deedacbbce
31-40 abdcebaeec
41-50 caadedbaea
51-60 edeacbacdd


1a)
Tabulate
x - 1, 2, 3, 4
1- 1, 2, 3, 4
2- 2_ , 4, 0 _ ,2 _
3- 3, 0 _, 3 , 0_
4- 4_ , 2_ , 0_ , 4
1b)
I = PRT /100, p =N15000 R =10 % and I =3years
A = P+ I
where I = 15000 * 10* 3/100= N4500
A =4500 +15000 =N 19500
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2a)
using sine rule
b/sin 20 = 6/sin 30
bsin 30 = 6sin 120
b 6 sin 120/sin 30
b = 6x 0 .2511 /0.4540
b = 5. 7063/0 .4540
b = 12. 57 ≠ 12 .6cm
2bi)
the diagram is euivalent triangles .
where
| AX| /| BC | = | BY| /| AC | = | XY| /| YC |
XY = 9, BY = 7
YC = 18 -7 =11
9/11 = 7 /| AC |
9| AC | = 77
| AC | = 77 /9
| AC | = 8cm
2bii )
XY/AB = BY/AC
9/| AB| = 7/8. 6
| AB| = 9x 8. 6/7
| AB| = 11cm
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3)
let the son age be x
man =5x
son=x
4yrs ago; the man age = 5x - 4
the son age = x - 4
the product of their ages
( 5x - 4) ( x - 4 ) =448
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4a)
volume of fuel = cross- sectional area of X depth
of fuel rectangular tank
30, 000 litres = 7 .5* 4.2 *d m^3
but ; 1000 litres =1m ^3
therefore ; 30 ( M^3) = 7 .5* 4.2 *d( M ^3)
30=31 .5d
====> d = 30/31 .5 = 0. 95( 2d .p)
4b)
to fill the tank /volume of fuel needed
= 7 .5* 4.2 *1. 2
= 37 .8m ^3
= 37 , 800 litres
addition fuel = 37 ,800 - 30, 000
= 7 ,800 litres
therefore , 7, 800 more litres would be needed
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6)
tabulate
No
41. 02sqr 0.7124
42. 81
0.207
0.0404
antilog ( 0. 6616 )
=4. 587
log
1.6130 ===> 1. 6130
T .8527 /2
=2^- + 1.8527 /2 +
T + 0.9264 ===> T .9264 1 .5394
1.6321
T .3160 +
2^- .6064
T .5545 ===> T .5545
1.9849 ===> 1. 9849 /3
= 0 .6616
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5a)
sector for building project
=48000 /144000 * 360= 120degree
sector for education =
32, 000 /144000 *360 =80 degree
sector for saving =
19200 /144000 * 360=48 degree
sector for maintenance =
12000 /144000 * 360=30 degree
sector for miscellaneous =
7200 /144000 *360 =18 degree
sector for food items = 360- ( 120+ 80+48 +30+18 )
=360 -296
=64degree
5b)
amount spent =144000 -
[48 ,000 +32000 +19200 + 12000 +7200 ]
=144000 - 118400
=N25600
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7a)
3^2n+ 1 - 4( 3 ^n+1) +9 =0
3^2- 3 - 4 ( 3^n - 3) +9 =0
( 3^n)^ 2- 3 - 4( 3^n -3) + 9=0
let 3^n = p
p^2 -3 - 4( p- 3) +9= 0
3p^2/3 - 12p /3 + 9/3 = 0
p^2 - 4p + 3 = 0
p^2 - 3p - p + 3 = 0
p^2p( p -3) - 1( p- 3) = 0
( p- 1) ( p- 3) = 0
p- 1 = 0 or p- 3 = 0
p = 1 or 3
Recall 3^n = p
when p= 1
3^n = 3^0
n = 0
when p = 3
3^n = 3^1
n = 1
7b)
log( x ^2+ 4) = 2+logx - log^20
log( x ^2+ 4) = log^100 = log^x - log ^20
( x ^2+4 ) = log( xx )
x ^2+4 = 5x
x ^2- 5x +4 = 0
x ^2- 4x - x +4 = 0
x ( x - 4) - 1 ( x -4 ) = 0
( x - 1) ( x - 4) = 0
x - 1 = 0 or x - 4 = 0
x = 1 or 4
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8a)
| AD | ^2= 13^2- 5^2
| AD | ^2= 169- 25
| AD | ^2= 144
AD= sqr144
AD= 12CM
| AD | =12 -r
r ^2=( 12 -r )^ 2 - 5^2
r ^2=( 12 -r ) ( 12 -r ) +25
r ^2=144 -24 r +25
r ^2=169 -24 r
r ^2+24 r -169 =0
r ^2+24 r =169
r ^2+24 r +14^2= 169+14 ^2
( r +14)^ 2 =169+ 196
( r +14)^ 2 =365
( r +14= sqr365
r +14= 19.105
r =19. 105- 14
r =5. 105
r =5. 1cm
8aii )
circumfrenece of a circle =2pie R
C =2 x 22/2* ( 5. 1)^ 2
C =1144 . 44/7
C =163 .4914 cm
C =163 .5 cm
8b)
y 2- y 1/x 2 -x 1 =y - y 1/x - x 1
6- 2/2- ( -1)= y -2 /x -( - 1)
4/2+1 = y -2 /x +1
4/3=y -2/x +1
3( y - 2)= 4( x +1)
3y - 6=4x +4
3y - 4x =4 +6
3y - 4x =10
y =4x /3+10/3
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9a)
let Xy represent the two digit number
x - y =5 -- -- - ( i )
3xy - ( 10 x +y )= 14
3xy - 10 x - y =14 -- - -( ii )
from eqn ( i )
x =5+ y
3y ( 5+ y ) -10 ( 5+y ) - y =14
15y + 3y ^2 - 50 - 10 y - y =14
3y ^2 + 4 y - 50 = 14
3y ^2 + 4 y - 50 - 14 = 0
3y ^2 + 4 y - 64 =0
3y ^2 + 12 y + 16y - 64 =0
( 3y ^2 - 12y ) ( +16y - 64)= 0
by
( y - 4) +16( y -4)= 0
( y - 4)= 0
ii )
( 3y +16 ) ( y - 4)= 0
3y +16 =0 or y - 4=0
3y =- 16 or y =4
y =- 16/3 or y =4
when y = 4
x =5+ y
x =5+ 4
x =9
the no is 94
9b)
3- 2x /4 + 2x -3/3
=3( 3- 2x ) + 4( 2x - 3) /12
=9- 6x +8 x -12 /12
=2x - 2/12
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10a)
y =( 2x ^2 + 3)^ 5
let U =2x ^2 + 3
Y =u^5
du/dx = 4x
dy /du = 5u^4
dy /du = ( 2x ^2 + 3)^ 4
dy /dx = du/dx dy /du
dy /dx = 4x .5 ( 2x ^2 + 3)^ 4
dy /dx = 20x ( 2x ^2 + 3)^ 4
10b)
y =3x ^2 + 2x +5
dy /dx =6x + 2
dy /dx =6( 3 ) +2
dy /dx =18 +2
dy /dx =20
10c )
R - W= Wv^2/gx
Wv^2=gx ( R - W)
Wv^2=gRx -Wgx
Wv^2+Wgx =gRx
W( v ^2 + gx ) =gRx
W= gRx /V ^2 + gx
R =2 , g=10 , x =3/2 , V =3
W= 10* 2* 3/2/3^2 + 10* 3/5
W= 30/9+15
W= 30/24
W= 5/4

COMPLETED